For a quadratic in standard form (y=ax^2+bx+c), use (x=-frac{b}{2a})
Substitute that (x)-value into the equation to find (y)
The vertex is (left(-frac{b}{2a},, fleft(-frac{b}{2a}right)right))
For a quadratic in vertex form (y=a(x-h)^2+k), the vertex is ((h,k))
If needed, complete the square to rewrite the equation in vertex form