For a quadratic function in standard form (f(x)=ax^2+bx+c), use (x=-frac{b}{2a})
Substitute that (x)-value into the function to find (y)
The vertex is (left(-frac{b}{2a}, fleft(-frac{b}{2a}right)right))
For a quadratic in vertex form (f(x)=a(x-h)^2+k), the vertex is ((h,k))
If the quadratic is factored, expand it first or use the axis of symmetry to find the vertex
The axis of symmetry is (x=-frac{b}{2a}) in standard form
The vertex is the maximum point if (a<0)
The vertex is the minimum point if (a>0)