For a quadratic function in standard form (f(x)=ax^2+bx+c), find the x-coordinate of the vertex using (x=-frac{b}{2a})
Substitute that x-value into the function to find the y-coordinate: (y=f!left(-frac{b}{2a}right))
The vertex is (left(-frac{b}{2a},, f!left(-frac{b}{2a}right)right))
For a quadratic in vertex form (f(x)=a(x-h)^2+k), the vertex is ((h,k))
For a quadratic in factored form (f(x)=a(x-r_1)(x-r_2)), find the x-coordinate with (x=frac{r_1+r_2}{2})
Substitute that x-value into the function to find the y-coordinate
The vertex is the turning point of the parabola