How To Find The Inverse Of Matrix 3×3?

Let the matrix be (A=begin{bmatrix}a&b&c\ d&e&f\ g&h&iend{bmatrix})

Compute the determinant:

[

det(A)=a(ei-fh)-b(di-fg)+c(dh-eg)

]

If (det(A)=0), the inverse does not exist

Find the cofactor matrix:

[

C=begin{bmatrix}

(ei-fh) & -(di-fg) & +(dh-eg)\

(bi-ch) & +(ai-cg) & -(ah-bg)\

(bf-ce) & -(af-cd) & +(ae-bd)

end{bmatrix}

]

Take the transpose of the cofactor matrix to get the adjugate:

[

operatorname{adj}(A)=C^T

]

Divide the adjugate by the determinant:

[

A^{-1}=frac{1}{det(A)}operatorname{adj}(A)

]

Write the inverse as:

[

A^{-1}=frac{1}{det(A)}

begin{bmatrix}

ei-fh & ch-bi & bf-ce\

fg-di & ai-cg & cd-af\

dh-eg & bg-ah & ae-bd

end{bmatrix}

]

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