If the parabola is in vertex form (y=a(x-h)^2+k), the vertex is ((h,k))
If the parabola is in standard form (y=ax^2+bx+c), find (x=-frac{b}{2a})
Substitute that (x)-value into the equation to find (y)
The vertex is (left(-frac{b}{2a},, f!left(-frac{b}{2a}right)right))
If the parabola opens up or down, the vertex is the minimum or maximum point
If the parabola is given in factored form, use symmetry or convert to standard form first