If the parabola is in vertex form (y=a(x-h)^2+k), the vertex is ((h,k))
If the parabola is in standard form (y=ax^2+bx+c), use (x=-frac{b}{2a})
Substitute (x=-frac{b}{2a}) into the equation to find (y)
The vertex is (left(-frac{b}{2a},, fleft(-frac{b}{2a}right)right))
If the parabola is given by a graph, the vertex is the highest or lowest point
If the parabola is in factored form, find the axis of symmetry by averaging the roots, then substitute that (x)-value into the equation