Put the equation in vertex form: (y=a(x-h)^2+k)
Identify the vertex directly as ((h,k))
If given in standard form (y=ax^2+bx+c), compute (x)-coordinate of the vertex:
(h=-dfrac{b}{2a})
Compute the (y)-coordinate by substituting (h) into the equation:
(k=f(h)=a h^2+b h+c)
If given in factored form (y=a(x-r_1)(x-r_2)):
Use (h=dfrac{r_1+r_2}{2})
Compute (k=f(h))
If completing the square:
Rewrite (ax^2+bx+c) as (aleft(x^2+frac{b}{a}xright)+c)
Complete the square to get (y=a(x-h)^2+k)
Read the vertex as ((h,k))